Question

A person of mass \( 60 \) kg is inside a lift of mass \( 940 \) kg. The lift starts moving upwards with an acceleration of \( 1.0 \) m/s\( ^2 \). If \( g = 10 \) m/s\( ^2 \), the tension in the supporting cable is:

• A. \( 8600 \) N
• B. \( 9680 \) N
• C. \( 11000 \) N
• D. \( 1200 \) N

Hint:

In an accelerating lift, the apparent weight is given by \( T = mg + ma \).

Answer 1

The Correct Option is C

Step 1: Calculate the aggregate mass.
\[ m_{{total}} = 60 + 940 = 1000 { kg} \] Step 2: Apply Newton’s Second Law.
\[ T - mg = ma \] Substitute values: \[ T - (1000 \times 10) = 1000 \times 1 \] \[ T = 10000 + 1000 = 11000 { N} \] The determined result is (C) 11000 N.