Question:medium

A person observes two moving trains. 'A' reaching the station and 'B' leaving the station with equal speed of 30m/s. If both trains emit sounds with frequency 300 Hz, (speed of sound = 330 m/s) difference of frequencies heard by the person will be

Show Hint

One train approaches and one recedes, so use the Doppler formula for each.
Updated On: Oct 1, 2026
  • \(10 \text{Hz}\)
  • \(33 \text{Hz}\)
  • \(55 \text{Hz}\)
  • \(80 \text{Hz}\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Compute ratios
Approaching: $\frac{330}{330-30} = 1.1$ gives $330$ Hz. Receding: $\frac{330}{330+30} = \frac{11}{12}$ gives $275$ Hz.

Step 2: Subtract
$55$ Hz. Option (C).

Final Answer:
55 Hz. \[ \boxed{\text{(C)}\ 55\ \text{Hz}} \]
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