Question

A particle of mass \( m \) is projected with a velocity \( v \) making an angle of \( 30^\circ \) with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height \( h \) is –

• A. \( \sqrt{3} \frac{m v^2}{g} \)
• B. zero
• C. \( \frac{m v^3}{2g} \)
• D. \( \sqrt{3} \frac{m v^3}{16 g} \)

Hint:

At the maximum height in projectile motion, the vertical velocity becomes zero, making the angular momentum zero.

Answer 1

The Correct Option is B