Question:medium

A particle of mass \(200 \text{ g}\) is executing S.H.M. of amplitude \(0.2 \text{ m}\). At mean position, K.E. is \(16 \times 10^{-3} \text{ J}\). The equation of motion is:

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The maximum velocity in S.H.M. occurs at the mean position and is equal to $\omega A$.
Updated On: Apr 30, 2026
  • \(Y = 0.2 \sin(4t)\)
  • \(Y = 0.2 \sin(\frac{t}{4})\)
  • \(Y = 0.2 \sin(\frac{t}{2})\)
  • \(Y = 0.2 \sin(2t)\)
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The Correct Option is D

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