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A particle is executing SHM of amplitude \(4\text{ cm}\) and time period \(4\text{ s}\). The time taken by it to move from positive extreme position to half the amplitude is
A particle is executing SHM of amplitude \(4\text{ cm}\) and time period \(4\text{ s}\). The time taken by it to move from positive extreme position to half the amplitude is
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Standard SHM time intervals to memorize:
• Mean position (\(0\)) to half amplitude (\(A/2\)): \(t = T/12\)
• Half amplitude (\(A/2\)) to extreme (\(A\)): \(t = T/6\)
• Extreme (\(A\)) to half amplitude (\(A/2\)): \(t = T/6\) Here, the particle moves from \(A\) to \(A/2\), so \(t = T/6 = 4/6 = 2/3\text{ s}\).
• Mean position (\(0\)) to half amplitude (\(A/2\)): \(t = T/12\)
• Half amplitude (\(A/2\)) to extreme (\(A\)): \(t = T/6\)
• Extreme (\(A\)) to half amplitude (\(A/2\)): \(t = T/6\) Here, the particle moves from \(A\) to \(A/2\), so \(t = T/6 = 4/6 = 2/3\text{ s}\).
Updated On: May 14, 2026
- \(1\text{ s}\)
- \(\frac{1}{3}\text{ s}\)
- \(\frac{2}{3}\text{ s}\)
- \(\sqrt{\frac{2}{3}}\text{ s}\)
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The Correct Option is C
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