Question

A parallel combination, as stated in (a) above, of two cells of emfs \(E\) and \(3E\) and internal resistances \(R\) each is connected across a resistance \(2R\). Find the current that flows through resistance \(2R\).

Hint:

For cells connected in parallel: \[ E_{\text{eq}} = \frac{E_1r_2+E_2r_1}{r_1+r_2} \] \[ r_{\text{eq}} = \frac{r_1r_2}{r_1+r_2} \] Always reduce the combination to a single equivalent cell before applying Ohm's law.

Answer 1