Question:medium

A mould cavity of $1200\text{ cm}^3$ volume has to be filled through a sprue of $10\text{ cm}$ length feeding a horizontal runner. Cross-sectional area at the base of the sprue is $2\text{ cm}^2$. Consider acceleration due to gravity as $9.81\text{ m/s}^2$. Neglecting frictional losses due to molten metal flow, the time taken to fill the mould cavity is}

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Always keep your units consistent.
Converting gravity $g = 9.81\text{ m/s}^2$ directly to $981\text{ cm/s}^2$ avoids the need to convert volume from $\text{cm}^3$ to $\text{m}^3$, saving computation steps.
Updated On: Jul 9, 2026
  • 4.28 s
  • 5.26 s
  • 7.23 s
  • 5.36 s
Show Solution

The Correct Option is A

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