Question

A monochromatic source of wavelength 600 nm was used in Young's double slit experiment to produce interference pattern. $I_1$ is the intensity of light at a point on the screen where the path difference is 150 nm. The intensity of light at a point where the path difference is 200 nm is given by

• A. $\frac{1}{2}I_1$
• B. $\frac{3}{2}I_1$
• C. $\frac{2}{3}I_1$
• D. $\frac{3}{4}I_1$
• E. $\frac{4}{3}I_1$

Hint:

Convert path difference to phase first.

Answer 1

The Correct Option is C