Question:medium

A monoatomic ideal gas, initially at temperature ' \(T_1\) ' is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature ' \(T_2\) ' by releasing the piston suddenly. \(L_1\) and \(L_2\) are the lengths of the gas columns before and after the expansion respectively. Then \(\frac{T_1}{T_2}\) is

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Adiabatic shortcut: $TV^{\gamma-1} = \text{constant}$
Updated On: May 8, 2026
  • \(\sqrt{\frac{L_1}{L_2}}\)
  • \(\sqrt{\frac{L_2}{L_1}}\)
  • \(\left(\frac{L_1}{L_2}\right)^{2/3}\)
  • \(\left(\frac{L_2}{L_1}\right)^{2/3}\)
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The Correct Option is C

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