Question:medium

A metre bridge experiment, the resistance in the left gap is \(20 \Omega\) and in the right gap is \(60 \Omega\). The bridge is balanced. The distance of the null point from the centre of the wire is

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At balance, R1/R2 = l/(100 - l).
Updated On: Oct 1, 2026
  • \(50\) cm
  • \(75\) cm
  • \(25\) cm
  • \(40\) cm
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Use resistance per length:
Total resistance $80\ \Omega$ is shared along 100 cm. Left $20\ \Omega$ takes $\dfrac{20}{80}$ of the length.

Step 2: Length:
$\dfrac{20}{80}\times100 = 25$ cm from the left.

Step 3: Offset from the centre:
$|50 - 25| = 25$ cm, option (C).

Final Answer:
The null point is 25 cm from the centre. \[ \boxed{\text{(C) }25\ \text{cm}} \]
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