The probabilities of members A, B, and C not attending are $P(A') = 0.10$, $P(B') = 0.20$, and $P(C') = 0.05$, respectively. The meeting is cancelled if at least one member is absent, which is given by $P(\text{cancelled}) = P(A' \cup B' \cup C')$. This can be calculated as $1 - P(A \cap B \cap C)$, where $P(A \cap B \cap C)$ is the probability that all three members attend. Assuming independence, $P(A \cap B \cap C) = P(A) \cdot P(B) \cdot P(C) = (1 - P(A')) \cdot (1 - P(B')) \cdot (1 - P(C')) = (1 - 0.10) \cdot (1 - 0.20) \cdot (1 - 0.05) = 0.90 \cdot 0.80 \cdot 0.95 = 0.684$. Therefore, the probability of the meeting being cancelled is $P(\text{cancelled}) = 1 - 0.684 = 0.316$.