Question

A mass of 0.5 kg is attached to a spring of force constant 200 N/m. What is the time period of oscillation?

• A. 0.314 s
• B. 0.451 s
• C. 0.567 s
• D. 0.789 s

Hint:

In mass-spring systems, use the formula \( T = 2 \pi \sqrt{\frac{m}{k}} \) to find the time period of oscillation.

Answer 1

The Correct Option is A

The oscillation period \( T \) for a mass-spring system is \( T = 2 \pi \sqrt{\frac{m}{k}} \). With \( m = 0.5 \) and \( k = 200 \), the calculation is \( T = 2 \pi \sqrt{\frac{0.5}{200}} \approx 0.314 \, \text{s} \). Therefore, the oscillation period is \( 0.314 \, \text{s} \).