Question:medium

A man standing between two parallel cliffs fires a gun. He hear two echos one after \(3\) second and the other after \(5\) second. The separation between the two cliffs is \(1360\) m, the speed of sound is

Show Hint

Each echo travels twice the distance to its cliff, and the two distances add up to the separation of the cliffs.
Updated On: Nov 12, 2026
  • \(320\) m/s
  • \(330\) m/s
  • \(340\) m/s
  • \(350\) m/s
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Distances
$2d_{1}=3v$ and $2d_{2}=5v$.

Step 2: Add
Adding gives $2(d_{1}+d_{2})=8v$, and $d_{1}+d_{2}=1360$ m, so $2720=8v$.

Step 3: Solve
$v=340$ m/s, option (C).

Final Answer:
The speed of sound is 340 m/s. \[ \boxed{\text{(C) }340\text{ m/s}} \]
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