Question:medium

A man invests ₹10,000 at 10% compound interest compounded annually; what is the total amount after 2 years?

Show Hint

For compound interest questions: \[ A = P \left(1 + \frac{r}{100}\right)^n \] Example shortcut for 2 years:
  • After 1 year: \(10000 \times 1.10 = 11000\)
  • After 2 years: \(11000 \times 1.10 = 12100\)
Memory trick: \[ \textbf{Compound Interest = Interest on Interest} \]
Updated On: Mar 16, 2026
  • ₹12,000
  • ₹12,100
  • ₹11,000
  • ₹12,200
Show Solution

The Correct Option is B

Solution and Explanation

This problem requires the calculation of the final amount on an investment using the formula for compound interest.
Step 1: Understanding the Question:
We need to find the total amount (Principal + Interest) after 2 years for a principal of Rs10,000 at a 10% annual compound interest rate.
Step 2: Key Formula or Approach: }
The formula for the amount (A) in compound interest is:
\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where:
P = Principal amount (Rs10,000)
r = Annual interest rate (10% or 0.10)
n = Number of times interest is compounded per year (annually, so n=1)
t = Number of years (2)
Step 3: Detailed Explanation:
Substitute the given values into the formula:
\[ A = 10000 \left(1 + \frac{0.10}{1}\right)^{1 \times 2} \] \[ A = 10000 (1 + 0.10)^2 \] \[ A = 10000 (1.1)^2 \] \[ A = 10000 \times 1.21 \] \[ A = 12100 \] The total amount after 2 years will be Rs12,100.
Alternatively, we can calculate year by year:

Interest for Year 1: 10% of Rs10,000 = Rs1,000.
Amount at the end of Year 1 = Rs10,000 + Rs1,000 = Rs11,000.

Interest for Year 2: 10% of Rs11,000 = Rs1,100.
Amount at the end of Year 2 = Rs11,000 + Rs1,100 = Rs12,100.

Step 4: Final Answer: }
The total amount after 2 years is Rs12,100.
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