Question:medium

A liquid is flowing through a tube of diameter 9 mm with a speed of \(10\,cm\,s^{-1}\). If this tube is connected to a narrow tube in which the liquid flows with a speed of \(90\,cm\,s^{-1}\), then the diameter of the narrow tube is:

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In continuity equation problems, always remember \(A \propto d^2\), not \(d\).
Updated On: Jun 19, 2026
  • 9 mm
  • 1 mm
  • 3 mm
  • 10 mm
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The Correct Option is C

Solution and Explanation

Step 1: Continuity principle.
For incompressible flow, A₁ v₁ = A₂ v₂, and since area ∝ diameter², d₁² v₁ = d₂² v₂.

Step 2: Inserting data.

(9)² × 10 = d₂² × 90.

Step 3: Simplifying.

81 × 10 = 90 d₂² → 810 = 90 d₂².

Step 4: Solving for diameter.

d₂² = 9 → d₂ = 3 mm.

Step 5: Conclusion.

The narrow tube's diameter is 3 mm.
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