Question

A liquid flows through two similar pipes 1 and 2. If the ratio of their flow velocities V$_1$:V$_2$ be 2:3, what will be the ratio of the head loss in the two pipes?

• A. 8:27
• B. $\sqrt{2}$:$\sqrt{3}$
• C. 2:3
• D. 4:9

Hint:

For similar pipes, the frictional head loss is proportional to the square of the velocity (\(h_f \propto V^2\)).
Simply square the velocity ratio to find the head loss ratio:
\[ (2:3)^2 \rightarrow 4:9 \] This relationship is highly common in pipeline design problems.

Answer 1

The Correct Option is D