Question:medium

A light metal disc of radius ' \(r\) ' floats on water surface and bends the surface downwards along the perimeter making an angle ' \(\theta\) ' with the vertical edge of the disc. If the weight of water displaced by the disc is ' W ', the weight of the metal disc is [ \(\text{T}\) = surface tension of water]

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Surface tension force: $F = 2\pi r T \cos\theta$
Updated On: May 8, 2026
  • \(\text{W} - 2\pi\text{rT} \cos \theta\)
  • \(2\pi r \text{ T} + \text{W}\)
  • \(2\pi\text{rT} \cos \theta + \text{W}\)
  • \(2\pi\text{rT} \cos \theta - \text{W}\)
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The Correct Option is C

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