Question:medium
A lamp consumes only 25% of the peak power in an AC circuit. The phase difference between the applied voltage and the current is
A lamp consumes only 25% of the peak power in an AC circuit. The phase difference between the applied voltage and the current is
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Power factor \(=\cos\phi\). Smaller power → larger phase difference.
Updated On: May 8, 2026
- \(\frac{\pi}{6}\)
- \(\frac{\pi}{3}\)
- \(\frac{\pi}{4}\)
- \(\frac{\pi}{2}\)
- \(\pi\)
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The Correct Option is B
Solution and Explanation
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