Question:medium

A group of 200 people are chosen randomly at a conference. Later, it was found that 120 of them like blue pens and 140 like green pens while 70 like both green and blue pens. Determine the number of people thus chosen who like neither green nor blue pens?

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Use inclusion-exclusion: $n(A \cup (b) = n((a) + n((b) - n(A \cap (b)$.
Updated On: Mar 30, 2026
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Show Solution

The Correct Option is C

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