Step 1: Problem Interpretation.
The objective is to calculate the total daily home-based trips for: - Households with a size of two or more persons (i.e., 2 persons or 3+ persons). - Households possessing one or more vehicles (i.e., categories "One (1)" and "Two & above (2+)"). Data from Table I (trip rates per household) and Table II (number of households) will be utilized.
Step 2: Data Extraction. From Table I – Trip rate of households: \[\begin{array}{|c|c|c|}\hline\text{Vehicles/household} & \text{Two (2)} & \text{Three & above (3+)}
\hline\text{One (1)} & 2.5 & 5
\text{Two & above (2+)} & 3 & 6
\hline\end{array}\] From Table II – Household composition: \[\begin{array}{|c|c|c|}\hline\text{Vehicles/household} & \text{Two (2)} & \text{Three & above (3+)}
\hline\text{One (1)} & 300 & 200
\text{Two & above (2+)} & 100 & 50
\hline\end{array}\]
Step 3: Trip Calculation (Households × Trip Rate). \[\text{Case 1: One vehicle, Two persons} = 300 \times 2.5 = 750\] \[\text{Case 2: One vehicle, Three+ persons} = 200 \times 5 = 1000\] \[\text{Case 3: Two+ vehicles, Two persons} = 100 \times 3 = 300\] \[\text{Case 4: Two+ vehicles, Three+ persons} = 50 \times 6 = 300\]
Step 4: Total Trip Summation. \[\text{Total Trips} = 750 + 1000 + 300 + 300 = 2350\] Verification required.
Step 5: Detailed Verification with Table II. - One vehicle, Two persons: \(300 \times 2.5 = 750\) - One vehicle, 3+ persons: \(200 \times 5 = 1000\) - Two+ vehicles, Two persons: \(100 \times 3 = 300\) - Two+ vehicles, 3+ persons: \(50 \times 6 = 300\) Sum: \(2350\).
Final Result: \[\boxed{2350}\]