Question

A gas occupies a volume of \(0.35\) dm\(^3\) at \(290\) K and \(2\) atm. Pressure. Calculate the volume of gas at STP.

• A. \(3.11\) dm\(^3\)
• B. \(0.66\) dm\(^3\)
• C. \(0.11\) dm\(^3\)
• D. \(3.5\) dm\(^3\)

Hint:

Use the combined gas law with STP of $273$ K and $1$ atm.

Answer 1

The Correct Option is B

Step 1: Convert to moles
$n=\frac{PV}{RT}=\frac{2\times0.35}{0.0821\times290}=0.0294$ mol. At STP $22.4$ dm$^3$/mol gives $0.0294\times22.4=0.66$ dm$^3$.

Final Answer:
Option (B). \[ \boxed{\text{(B)}} \]