Let \( x \), \( y \), and \( z \) represent the quantities of chairs, tables, and beds produced, respectively. The problem is defined by the following system of equations: 1. \( x + y + z = 45 \) (total furniture production) 2. \( z = x + 8 \) (bed production exceeds chair production by 8) 3. \( x + z = 2y \) (combined production of beds and chairs equals twice the table production) This system can be expressed in matrix form: \[ \begin{bmatrix} 1 & 1 & 1 \\ 1 & 0 & -1 \\ 1 & -2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 45 \\ 8 \\ 0 \end{bmatrix} \] To solve this system using matrix algebra, we first determine the inverse of the coefficient matrix \( A = \begin{bmatrix} 1 & 1 & 1 \\ 1 & 0 & -1 \\ 1 & -2 & 1 \end{bmatrix} \). The determinant of \( A \) is calculated as: \[ \text{det}(A) = 1 \cdot \begin{vmatrix} 0 & -1 \\ -2 & 1 \end{vmatrix} - 1 \cdot \begin{vmatrix} 1 & -1 \\ 1 & 1 \end{vmatrix} + 1 \cdot \begin{vmatrix} 1 & 0 \\ 1 & -2 \end{vmatrix} \] \[ \text{det}(A) = 1 \cdot ((0 \cdot 1) - (-1 \cdot -2)) - 1 \cdot ((1 \cdot 1) - (-1 \cdot 1)) + 1 \cdot ((1 \cdot -2) - (1 \cdot 0)) \] \[ \text{det}(A) = 1 \cdot (-2) - 1 \cdot (2) + 1 \cdot (-2) = -2 - 2 - 2 = -6 \] After computing the inverse of \( A \), the system is solved to find the values of \( x \), \( y \), and \( z \). The solution yields: \( x = 17, \quad y = 14, \quad z = 18 \). Therefore, 17 chairs, 14 tables, and 18 beds were produced.