Question:medium

A full-wave rectifier has a peak voltage of \(100\,\text{V}\). The average output voltage is

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For a full-wave rectifier, \[ \boxed{ V_{\text{avg}}=\frac{2V_m}{\pi}\approx0.637V_m. } \]
Updated On: Jul 14, 2026
  • \(31.8\,\text{V}\)
  • \(50\,\text{V}\)
  • \(63.7\,\text{V}\)
  • \(70.7\,\text{V}\)
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The Correct Option is C

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