Step 1: Understanding the Topic:
This question comes from the "Kinetic Theory of Gases." It explores the relationship between the thermal energy of gas particles and their microscopic speeds. A key takeaway is that at a specific temperature, different gas molecules have different average speeds based on their masses.
Step 2: Key Formulas and Approach:
The root mean square speed ($v_{rms}$) is defined as:
\[ v_{rms} = \sqrt{\frac{3RT}{M}} \]
Where:
$R$ is the universal gas constant.
$T$ is the absolute temperature (in Kelvin).
$M$ is the molar mass (or molecular mass) of the gas.
Step 3: Detailed Explanation:
Analyze the environment: Both gases are in the same flask, meaning they are in thermal equilibrium at the same temperature ($T = 27^\circ \text{C} = 300 \text{ K}$).
Establish the relationship: Since $3, R,$ and $T$ are constant for both gases, we can say $v_{rms} \propto \frac{1}{\sqrt{M}}$.
Identify masses: Molecular mass of Argon ($M_{Ar}$) = 40 u. Molecular mass of Chlorine ($M_{Cl_2}$) = 70 u. Note that the 2:1 mass ratio of the mixture is a "distractor" and does not affect the speed of individual molecules.
Formulate the ratio:
\[ \frac{v_{rms}(Ar)}{v_{rms}(Cl_2)} = \frac{\sqrt{3RT/M_{Ar}}}{\sqrt{3RT/M_{Cl_2}}} = \sqrt{\frac{M_{Cl_2}}{M_{Ar}}} \]
Substitute and calculate:
\[ \text{Ratio} = \sqrt{\frac{70}{40}} = \sqrt{\frac{7}{4}} = \frac{\sqrt{7}}{2} \]
Step 4: Final Answer:
The ratio of the rms speeds is $\sqrt{7}/2$.