Question:medium

A first-order reaction has a half-life of 693 sec. What will be its rate constant?

Updated On: Mar 27, 2026
  • 0.001 sec-1
  • 1 sec-1
  • 0.01 sec-1
  • 0.1 sec-1
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The Correct Option is A

Solution and Explanation

The rate constant (k) for a first-order reaction is related to its half-life (t1/2) by the equation: t1/2 = 0.693/k.

Given: \(t_{\frac {1}{2}} = 693\) sec.

Substitute the given half-life into the formula: \(693 = \frac {0.693}{k}\).

To solve for k, rearrange the equation: \( k = \frac {0.693}{693}\).

Performing the calculation: \( k = 0.001\ sec^{-1}\).

The calculated rate constant is \(0.001\ sec^{-1}\).

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