Question:medium

A fires 5 shots to B's 3, but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, how many times has A killed?

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Standardize the number of shots fired by one person to find the equivalent number fired by the other using the given ratio.
Updated On: Jun 15, 2026
  • 15
  • 30
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  • 25
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Set up a ratio based on the number of shots, hits (kills), and misses for both individuals.
Step 2: Identifying the Vector of Change:
- B's hit rate: 1 kill in 2 shots (Meaning 1 miss in 2 shots). - If B missed 27 times, B must have fired $27 \times 2 = 54 \text{ shots}$.
Step 3: Calculation:
- Ratio of A's shots to B's shots = $5 : 3$. - If B fired 54 shots, A fired: $(5/3) \times 54 = 5 \times 18 = 90 \text{ shots}$. - A's hit rate: 1 kill in 3 shots. - A's total kills = $90 / 3 = 30 \text{ kills}$.
Step 4: Final Answer:
A has killed 30 times. Thus, the correct option is (b).
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