Question:medium

(a) Define atomic mass unit (u).
(b) Calculate the energy required to separate a deuteron into its constituent parts (a proton and a neutron).
\( m_D = 2.014102 \, u} \)
\( m_H = 1.007825 \, u} \)
\( m_n = 1.008665 \, u} \)

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Understanding the concept of mass defect and binding energy is crucial for explaining why nuclei are stable and the energy processes involved in nuclear reactions.
Updated On: Jan 13, 2026
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Solution and Explanation

The atomic mass unit (u), also known as the unified atomic mass unit, is defined as one twelfth of the mass of an unbound neutral atom of carbon-12. This can be represented as: \[ 1 \, u} = \frac{1}{12} \times mass of one carbon-12 atom} \] The atomic mass unit is approximately: \[ 1 \, u} = 1.66053906660 \times 10^{-27} \, kg} \] It serves as a standard unit for expressing atomic and molecular weights. % Part (b) Calculation of Separation Energy (b) Calculation of Separation Energy:
The mass defect (\(\Delta m\)) is calculated as follows: \[ \Delta m = \left( m_{H}} + m_{n}} \right) - m(D) \] Substituting the provided values: \[ \Delta m = (1.007825 \, u} + 1.008665 \, u}) - 2.014102 \, u} \] \[ \Delta m = 2.016490 \, u} - 2.014102 \, u} = 0.002388 \, u} \] Next, convert the mass defect from atomic mass units to kilograms, using the approximation 1 u = \(1.660539 \times 10^{-27}\) kg: \[ \Delta m = 0.002388 \, u} \times 1.660539 \times 10^{-27} \, kg/u} = 3.965 \times 10^{-30} \, kg} \] Calculate the energy using \(E = \Delta m \cdot c^2\), with \(c = 3 \times 10^8 \, m/s}\): \[ E = 3.965 \times 10^{-30} \, kg} \times (3 \times 10^8 \, m/s})^2 \] \[ E = 3.965 \times 10^{-30} \, kg} \times 9 \times 10^{16} \, m}^2/s}^2 = 3.5685 \times 10^{-13} \, J} \] To express the energy in MeV, using the conversion 1 MeV = \(1.60218 \times 10^{-13}\) J: \[ E = \frac{3.5685 \times 10^{-13} \, J}}{1.60218 \times 10^{-13} \, J/MeV}} \approx 2.23 \, MeV} \] Consequently, the energy required to separate a deuteron into a proton and a neutron is approximately \boxed{2.23 \, MeV}}.
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