A decimolar solution potassium ferrocyanide is 50% dissociated at 300 K. The osmotic pressure of solution is (R = 8.314 J K$^{-1}$ mol$^{-1}$):

Question

A 200 g sample of water at 80°C is mixed with 100 g of water at 20°C. Assuming no heat loss to the surroundings, what is the final temperature of the mixture?

Answer 1

Step 1: Degree of Dissociation ($\alpha$) and Van't Hoff Factor ($i$)
The dissociation reaction for K$_4$[Fe(CN)$_6$] is:\[K_4[Fe(CN)_6] \rightleftharpoons 4K^+ + [Fe(CN)_6]^{4-}\]Given a 50% dissociation ($\alpha = 0.5$), the total number of particles is calculated as:\[i = 1 + 4\alpha = 1 + 4(0.5) = 3\]Step 2: Applying the Osmotic Pressure Formula
\[\pi = iCRT\]Substituting the calculated and given values:\[\pi = (3)(0.1)(8.314)(300)\]\[\pi = 7.48 { atm}\]Therefore, the correct answer is (A).

A decimolar solution potassium ferrocyanide is 50% dissociated at 300 K. The osmotic pressure of solution is (R = 8.314 J K$^{-1}$ mol$^{-1}$):

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The Correct Option is A

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