Question:medium

A DC generator with 8-pole, 480 armature conductors, wave winding, draws an armature current of 200 A. When brushes are shifted by \( 6^\circ \) electrical from GNP, the cross-magnetising amp-turn/pole is

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The fraction of demagnetising turns when brush shift is given in electrical degrees ($\theta_e$) is always $\frac{\theta_e}{90^\circ}$. - Calculate $AT_{\text{total}} = \frac{Z I_a}{2 P A}$. - Compute $AT_d = AT_{\text{total}} \cdot \frac{\theta_e}{90^\circ}$. - Find $AT_c = AT_{\text{total}} - AT_d$.
Updated On: Jun 25, 2026
  • \( 2200 \)
  • \( 200 \)
  • \( 800 \)
  • \( 2800 \)
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The Correct Option is D

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