A DC generator with 8-pole, 480 armature conductors, wave winding, draws an armature current of 200 A. When brushes are shifted by \( 6^\circ \) electrical from GNP, the cross-magnetising amp-turn/pole is
Show Hint
The fraction of demagnetising turns when brush shift is given in electrical degrees ($\theta_e$) is always $\frac{\theta_e}{90^\circ}$.
- Calculate $AT_{\text{total}} = \frac{Z I_a}{2 P A}$.
- Compute $AT_d = AT_{\text{total}} \cdot \frac{\theta_e}{90^\circ}$.
- Find $AT_c = AT_{\text{total}} - AT_d$.