Question

A current of 4 A is flowing at 230 V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2300 V and 40 % of power is lost, then the current in the secondary will be

• A. \(0.24\) A
• B. \(0.2\) A
• C. \(0.12\) A
• D. \(0.4\) A

Hint:

Output power is 60 percent of input power, then divide by the secondary voltage.

Answer 1

The Correct Option is A

Step 1: Approach
Compute the ideal current first and scale.

Step 2: Ideal case
$I_s=\dfrac{230\times4}{2300}=0.4$ A.

Step 3: With loss
Only 60 percent of the power gets out, so $I_s=0.6\times0.4=0.24$ A. Option (A).

Final Answer:
The output power is 552 W at 2300 V, so the secondary current is 0.24 A, option (A). \[ \boxed{0.24\ \text{A}} \]