A cube of side 40 cm is floating with $\frac{1}{4}$th of its volume immersed in water. When a circular disc is placed on the cube, it floats with $\frac{2}{5}$th of its volume immersed in water. The mass of the disc is
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In buoyancy problems, the weight of the floating object (or combination of objects) is always equal to the weight of the fluid it displaces. The weight of the disc is simply the weight of the additional volume of water displaced when it was added.