Step 1: Apply the lens formula The lens formula is expressed as:\[\frac{1}{f} = \frac{1}{v} - \frac{1}{u}\]where \( u \) is the object distance, \( v \) is the image distance, and \( f \) is the focal length.Step 2: Utilize the magnification formula Magnification (\( M \)) is calculated using:\[M = \frac{\text{Image height}}{\text{Object height}} = \frac{v}{u}\]Step 3: Substitute known values into the lens formula Given:- \( f = 10 \, \text{cm} \),- \( u = -30 \, \text{cm} \) (object distance is conventionally negative).Using the lens formula to determine \( v \):\[\frac{1}{10} = \frac{1}{v} - \frac{1}{-30}\]This simplifies to:\[\frac{1}{10} = \frac{1}{v} + \frac{1}{30}\]Solving for \( \frac{1}{v} \):\[\frac{1}{v} = \frac{1}{10} - \frac{1}{30} = \frac{3 - 1}{30} = \frac{2}{30} = \frac{1}{15}\]Thus:\[v = 15 \, \text{cm}\]Step 4: Compute the magnification Using the magnification formula:\[M = \frac{v}{u} = \frac{15}{-30} = -\frac{1}{2}\]The negative sign signifies an inverted image.Answer: The magnification is \( -\frac{1}{2} \). The magnitude of the magnification is \( 2 \). The correct option is (1).