To solve this problem, we need to determine the velocity of efflux of water from a container that has two layers of liquids: water and kerosene. We'll use Torricelli's theorem, which relates the velocity of efflux (v) to the height (h) of the liquid column above the hole.
The effective height (h) of the liquid column can be calculated by considering the pressure contribution of both water and kerosene.
\(P_{\text{water}} = \rho_{\text{water}} \cdot g \cdot h_{\text{water}}\)
where:
- \(\rho_{\text{water}} = 1000 \, \text{kg/m}^3\) (density of water)
- \(g = 9.8 \, \text{m/s}^2\) (acceleration due to gravity)
- \(h_{\text{water}} = 0.1 \, \text{m}\) (height of the water column)
\(P_{\text{kerosene}} = \rho_{\text{kerosene}} \cdot g \cdot h_{\text{kerosene}}\)
where:
- \(\rho_{\text{kerosene}} = 0.8 \cdot 1000 \, \text{kg/m}^3 = 800 \, \text{kg/m}^3\) (density of kerosene considering specific gravity)
- \(h_{\text{kerosene}} = 0.2 \, \text{m}\) (height of the kerosene column)
\(h_{\text{eff}} = \frac{P_{\text{water}} + P_{\text{kerosene}}}{\rho_{\text{water}} \cdot g}\)
This simplifies to:
\(h_{\text{eff}} = h_{\text{water}} + \frac{\rho_{\text{kerosene}}}{\rho_{\text{water}}} \cdot h_{\text{kerosene}}\)
\(h_{\text{eff}} = 0.1 + \frac{800}{1000} \cdot 0.2 = 0.1 + 0.16 = 0.26 \, \text{m}\)
\(v = \sqrt{2 \cdot g \cdot h_{\text{eff}}}\)
Substitute the values:
\(v = \sqrt{2 \cdot 9.8 \cdot 0.26} \approx 2.3 \, \text{m/s}\)
Thus, the velocity of efflux of water is 2.3 m/s, which matches option: \(2.3 \, \text{m/s}\).

