Question

A conducting sphere of radius $0.1\,\text{m}$ has uniform charge density $1.8\,\mu\text{C/m}^2$ on its surface. The electric field in free space at a radial distance $0.2\,\text{m}$ from the centre is ($\epsilon_0$ = permittivity of free space)

• A. $\frac{6\times10^{-6}}{\epsilon_{0}}Vm^{-1}$
• B. $\frac{6\times10^{-8}}{\epsilon_{0}}Vm^{-1}$
• C. $\frac{2\times10^{-7}}{\epsilon_{0}}Vm^{-1}$
• D. $\frac{1\times10^{-7}}{\epsilon_{0}}Vm^{-1}$

Hint:

Physics Tip : For any point outside a conducting sphere, the field behaves as if all the charge is concentrated at the geometric center. Always measure your "R" from the center, not the surface!

Answer 1

The Correct Option is C