Question

A compound with a molecular formula of C₆H₁₄ has two tertiary carbons. Its IUPAC name is:

• A. n-hexane
• B. 2-methylpentane
• C. 2,3-dimethylbutane
• D. 2,2-dimethylbutane

Answer 1

The Correct Option is C

Step 1: Molecular Formula and Classification

The compound's formula is \( C_6H_{14} \), signifying it is an alkane with six carbons and fourteen hydrogens.

Step 2: Definition of Tertiary Carbon

A tertiary carbon is defined as a carbon atom bonded to three other carbon atoms. The target compound requires exactly two such tertiary carbons.

Step 3: Evaluation of Isomers

• 2-Methylpentane: Possesses a single tertiary carbon.
• 2,3-Dimethylbutane: Contains two tertiary carbons, located at positions C2 and C3.
• 2,2-Dimethylbutane: Features only one tertiary carbon.
• n-Hexane: Lacks any tertiary carbons.

Step 4: Final Determination

2,3-Dimethylbutane is the correct isomer, fulfilling the condition of having two tertiary carbons.