Question:medium

A compound is formed by \(A\) (cations), \(B\) (cations) and \(O\) (anions). Atoms of \(O\) form a ccp lattice. Atoms of \(A\) occupy \(50\%\) of octahedral voids and atoms of \(B\) occupy \(25\%\) of tetrahedral voids. What is the molecular formula of the compound?

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For a ccp (fcc) lattice containing \(N\) particles: \[ \text{Octahedral voids}=N \] \[ \text{Tetrahedral voids}=2N \] Always calculate the number of ions occupying the voids and then reduce the ratio to obtain the empirical formula.
Updated On: Jul 29, 2026
  • \(AB_2O_4\)
  • \(AB_2O_2\)
  • \(ABO_3\)
  • \(ABO_2\)
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The Correct Option is D

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