Question:hard

A certain disease has a prevalence of \(1\%\) in the population. A diagnostic test for the disease has a sensitivity of \(98\%\) and a specificity of \(95\%\). If a person from this population tests positive, then the probability that they actually have the disease is...

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Apply Bayes' theorem with prevalence 1 percent, sensitivity 98 percent and false positive rate 5 percent.
Updated On: Oct 1, 2026
  • \(98\%\)
  • \(95\%\)
  • \(16.5\%\)
  • \(1\%\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Plan:
Use a population of $10{,}000$ people and count.

Step 2: Count:
Diseased: $100$. Of these, $98$ test positive. Healthy: $9900$. Of these, $5\%$ test positive, i.e. $495$.
Total positives: $98 + 495 = 593$. The share who really have the disease: $\frac{98}{593} \approx 0.165 = 16.5\%$.

Final Answer:
The probability that the person has the disease is about $16.5\%$, option (C). \[ \boxed{16.5\%} \]
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