Question:medium

A Carnot engine operates between a heat source at $T_1 = 600\text{ K}$ and a sink at $T_2 = 300\text{ K}$. If the engine absorbs $1000\text{ J}$ of heat from the source per cycle, the work done per cycle is:

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The temperature of the sink is exactly half of the source temperature, giving an efficiency of exactly $50\%$. Thus, half of the absorbed heat ($500\text{ J}$) is converted into useful work.
Updated On: May 31, 2026
  • $500\text{ J}$
  • $1000\text{ J}$
  • $250\text{ J}$
  • $750\text{ J}$
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The Correct Option is A

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