Question:medium
A Carnot engine is working between a source at constant temperature \(T_1\) and a sink at temperature \(T_2\). Its efficiency is \(\frac{1}{8}\). Upon decreasing the temperature of the sink by 50°C, the efficiency becomes \(\frac{1}{4}\). Find \(T_1\) and \(T_2\).
A Carnot engine is working between a source at constant temperature \(T_1\) and a sink at temperature \(T_2\). Its efficiency is \(\frac{1}{8}\). Upon decreasing the temperature of the sink by 50°C, the efficiency becomes \(\frac{1}{4}\). Find \(T_1\) and \(T_2\).
Show Hint
Always convert °C to K in thermodynamics before applying Carnot efficiency.
Updated On: Jun 20, 2026
- \(T_1 = 127^\circ C, \; T_2 = 77^\circ C\)
- \(T_1 = 400^\circ C, \; T_2 = 315^\circ C\)
- \(T_1 = 215^\circ C, \; T_2 = 100^\circ C\)
- \(T_1 = 100^\circ C, \; T_2 = 215^\circ C\)
Show Solution
The Correct Option is A
Solution and Explanation
Was this answer helpful?
0
Top Questions on carnot cycle
- A Carnot engine operates between temperatures of $ 600 \, \text{K} $ and $ 300 \, \text{K} $. If it absorbs $ 900 \, \text{J} $ of heat from the source, how much work does it perform?
- BITSAT - 2025
- Physics
- carnot cycle
- An ideal refrigerator has a freezer at a temperature of 130C. The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) is
- BITSAT - 2010
- Physics
- carnot cycle
A cyclic process ABCD is shown in the figure P-V diagram. Which of the following curves represent the same process?
- BITSAT - 2021
- Physics
- carnot cycle
- A geyser heats water flowing at a rate of 2.0 kg per minute from 30°C to 70°C. If geyser operates on a gas burner, the rate of combustion of fuel will be __________ g min–1.
[Heat of combustion = 8 × 103 Jg–1, Specific heat of water = 4.2 Jg–1 °C–1]- JEE Main - 2022
- Physics
- carnot cycle
- Want to practice more? Try solving extra ecology questions todayView All Questions