Question

A carbon resistor of (47 ± 4.7) kΩ is to be marked with rings of different colours for its identification. The colour code sequence will be

• A. Violet – Yellow – Orange – Silver
• B. Yellow – Green – Violet – Gold
• C. Yellow – Violet – Orange – Silver
• D. Green – Orange – Violet – Gold

Answer 1

The Correct Option is C

 To determine the correct color code for the given carbon resistor, we follow the standard resistor color-coding scheme. This involves assigning colors to numbers based on their sequence in a defined table. Here's the procedure to solve this question:

1. The carbon resistor is given as \(47 \, \text{k}\Omega\) with a tolerance of \(\pm 4.7\). We have to identify colors corresponding to the digits "47" and the power of 10 factor, as well as the tolerance level.
2. In the resistor color code, the numbers and their respective colors are as follows:

Color	Digit
Black	0
Brown	1
Red	2
Orange	3
Yellow	4
Green	5
Blue	6
Violet	7
Gray	8
White	9

1. The first two bands represent the first two significant digits of the resistance. The value '47' indicates:
   • First digit: '4' corresponds to the color Yellow.
   • Second digit: '7' corresponds to the color Violet.
2. The third band is a multiplier. '47 kΩ' indicates '47 x 10³', so the color for the multiplier (10³) is Orange.
3. The fourth band indicates tolerance. A tolerance of \(\pm 4.7\%\) corresponds to the color Silver (which signifies 10%).
4. Putting all these together, the color code is: Yellow – Violet – Orange – Silver.

Therefore, the correct color code for the given resistor is Yellow – Violet – Orange – Silver, corresponding to the option:

Yellow – Violet – Orange – Silver

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