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Centripetal forces
a car of mass m is crossi...
Question:
easy
A car of mass m is crossing the convex bridge of radius of curvature R with speed V. At the highest point the thrust is (\(g\) = gravitational acceleration)
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At the top, weight minus normal reaction provides the centripetal force.
MHT CET - 2026
MHT CET
Updated On:
Oct 1, 2026
\(mg\)
\(\frac{mv^2}{R}\)
\(mg-\frac{mv^2}{R}\)
\(mg+\frac{mv^2}{R}\)
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The Correct Option is
C
Solution and Explanation
Step 1: Forces
Down: $mg$. Up: $N$. Direction to the centre: down.
Step 2: Equation
Net inward force $= mg - N = mV^2/R$.
Step 3: Result
$N = mg - mV^2/R$. Option (C).
Final Answer:
Option (C). \[ \boxed{mg - \frac{mV^2}{R}} \]
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