
Each wiper blade, with a length of 25 cm, sweeps a sector of 115° within a circle.
Area of one sector = \(\frac{115° }{ 360°} \times \pi \times (25)^2\)
= \(\frac{23}{ 72} \times \frac{22} 7 \times 25 \times 25\)
= \(\frac{158125 }{ 252}\, cm^2\)
Total area swept by both blades = \(2 \times \frac{158125}{ 252}\) = \(\frac{158125} { 126}\, cm^2 \)