Question:medium

A boy stands \(x\ \text{m}\) away from a high wall and claps his hands at a steady rate so that each clap coincides with the echo of the one before. If he makes \(60\) claps in \(2\) minutes and the velocity of sound is \(340\ \text{m/s}\), then the distance \(x\) from the wall is

Show Hint

Find the time between claps. That interval equals the time for sound to go to the wall and back.
Updated On: Nov 12, 2026
  • \(170\ \text{m}\)
  • \(340\ \text{m}\)
  • \(255\ \text{m}\)
  • \(510\ \text{m}\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Total distance
In the interval of $2\ \text{s}$, sound travels $340\times2=680\ \text{m}$.

Step 2: Round trip
This distance covers the trip to the wall and back, so it is $2x$.

Step 3: Result
$x=\dfrac{680}{2}=340\ \text{m}$, option (B).

Final Answer:
The distance is 340 m. \[ \boxed{\text{(B) }\text{340 m}} \]
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