Step 1: Find the frequency
In medium P: $f = \dfrac{v_P}{\lambda_P} = \dfrac{0.8}{0.15} = 5.33$ Hz.
Step 2: Use it in Q
$v_Q = f\lambda_Q = 5.33\times0.30$.
Step 3: Compute
$v_Q = 1.6$ m/s.
Step 4: Check
The wavelength doubles, so the speed doubles from 0.8 m/s to 1.6 m/s. Options 4.0, 3.2 and 2.0 m/s do not match.
Step 5: Check the other options
The frequency is $\dfrac{0.8}{0.15} = 5.33$ Hz. A speed of 4.0 m/s in Q would need a wavelength of $\frac{4.0}{5.33} = 0.75$ m, and 3.2 m/s would need 0.6 m, and 2.0 m/s would need 0.375 m. None of these is the stated 0.30 m, so only 1.6 m/s fits.
Final Answer:
The velocity in Q is 1.6 m/s. This is option (D).
\[ \boxed{\text{(D) }1.6\ \text{m s}^{-1}} \]