Question:medium

A body performing uniform circular motion of radius $R$ has frequency $n$. Its centripetal acceleration is

Show Hint

You can use standard dimensional analysis to double-check your answer quickly! Acceleration must have dimensions of $\text{LT}^{-2}$. Frequency $n$ has units of $\text{s}^{-1}$ ($\text{T}^{-1}$) and radius $R$ has units of $\text{m}$ ($\text{L}$). Checking option (B): $n^2 R \rightarrow (\text{s}^{-2})(\text{m}) = \text{m/s}^2$. This matches the dimensions of acceleration perfectly!
Updated On: Jun 18, 2026
  • $8\pi^2 nR^2$
  • $4\pi^2 n^2 R$
  • $4\pi^2 n^2 R^2$
  • $8\pi^2 n^2 R$
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
Verify which expression for centripetal acceleration is dimensionally consistent using standard dimensional analysis.

Step 2: Key Formula or Approach:

Acceleration has dimensions of LT⁻². Frequency n has dimensions T⁻¹, and radius R has dimensions L. Combine these to test each candidate expression.

Step 3: Detailed Explanation:

Testing option (B): n²R yields (T⁻¹)² × L = T⁻²L = LT⁻², which perfectly matches the dimensions of acceleration. Other options produce mismatched dimensions like LT⁻¹ or L²T⁻². Dimensional analysis provides a rapid independent verification without recalling the exact formula, serving as an excellent exam double-check.

Step 4: Final Answer:

The expression n²R is dimensionally correct for acceleration.
Was this answer helpful?
0