To address the problem, it is necessary to comprehend the kinetic energy of an object traversing a circular trajectory at a uniform velocity.
- Kinetic energy (KE) is contingent upon the mass and velocity of the object.
- Equation:
\[
KE = \frac{1}{2} m v^2
\]
where \( m \) denotes mass and \( v \) signifies speed.
- In circular motion at a constant speed, the object's velocity vector alters direction, yet its speed (the magnitude of velocity) is invariant.
- Given that kinetic energy is solely dependent on speed, not direction, the KE remains unchanged during circular motion.
- Despite the object experiencing acceleration towards the center (centripetal acceleration), this does not affect its speed.
- Consequently, the kinetic energy remains constant provided the speed is maintained.
The kinetic energy of an object executing circular motion at a steady speed is unchanging.
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)? 