Question:medium

A body (mass $m$) starts its motion from rest from a point distant $R_0$ ($R_0>R$) from the centre of the earth. The velocity acquired by the body when it reaches the surface of earth will be ($G =$ universal constant of gravitation, $M =$ mass of earth, $R =$ radius of earth)}

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In central force fields like gravity, loss in Potential Energy equals gain in Kinetic Energy.
Updated On: Apr 28, 2026
  • 2GM \left( \frac{1}{R} - \frac{1}{R_0} \right)
  • \left[ 2GM \left( \frac{1}{R} - \frac{1}{R_0} \right) \right]^{\frac{1}{2
  • GM \left( \frac{1}{R} - \frac{1}{R_0} \right)
  • 2GM \left[ \left( \frac{1}{R} - \frac{1}{R_0} \right) \right]^{\frac{1}{2
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The Correct Option is A

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