Question:medium

A body is thrown with a velocity of \( 9.8 \) m/s making an angle of \( 30^\circ \) with the horizontal. It will hit the ground after a time:

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The total time of flight for projectile motion is: \[ T = \frac{2 u \sin \theta}{g} \] This formula is useful for determining how long a projectile remains in the air.
Updated On: Jan 13, 2026
  • \( 3.0 \) s
  • \( 2.0 \) s
  • \( 1.5 \) s
  • \( 1.0 \) s
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The Correct Option is D

Solution and Explanation

Step 1: {Apply the time of flight equation}
The formula for the time of flight of a projectile is:\[T = \frac{2 u \sin \theta}{g}\]Step 2: {Insert given values}
\[T = \frac{2 \times 9.8 \times \sin 30^\circ}{9.8}\]Step 3: {Calculate T}
\[T = \frac{2 \times 9.8 \times \frac{1}{2}}{9.8}\]\[T = 1 { sec}\]Therefore, the correct option is (D) 1.0 s.
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