A body is thrown with a velocity of \( 9.8 \) m/s making an angle of \( 30^\circ \) with the horizontal. It will hit the ground after a time:
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The total time of flight for projectile motion is:
\[
T = \frac{2 u \sin \theta}{g}
\]
This formula is useful for determining how long a projectile remains in the air.
Step 1: {Apply the time of flight equation} The formula for the time of flight of a projectile is:\[T = \frac{2 u \sin \theta}{g}\]Step 2: {Insert given values} \[T = \frac{2 \times 9.8 \times \sin 30^\circ}{9.8}\]Step 3: {Calculate T} \[T = \frac{2 \times 9.8 \times \frac{1}{2}}{9.8}\]\[T = 1 { sec}\]Therefore, the correct option is (D) 1.0 s.