A body is projected from a point which is at a height of \(5\) m from the ground with a velocity of \(28\ \mathrm{ms^{-1}}\) at an angle of \(30^\circ\) above the horizontal. The horizontal distance travelled by the body when it reaches a point which is at a height of \(2\) m from the ground is
\[
(g=10\ \mathrm{ms^{-2}})
\]
Show Hint
For projectile motion,
\[
\boxed{
y=y_0+u\sin\theta\,t-\frac12gt^2
}
\]
is used to find the time, and then
\[
\boxed{x=u\cos\theta\,t}
\]
gives the horizontal distance.