Question:medium
A body hanging from a massless spring stretches it by 3 cm on earth's surface. At a place 800 km above the earth's surface, the same body will stretch the spring by (Radius of earth = 6400 km)
A body hanging from a massless spring stretches it by 3 cm on earth's surface. At a place 800 km above the earth's surface, the same body will stretch the spring by (Radius of earth = 6400 km)
Show Hint
Spring extension depends directly on weight, so it changes with gravity.
Updated On: May 2, 2026
- $\frac{34}{27}$ cm
- $\frac{64}{27}$ cm
- $\frac{27}{64}$ cm
- $\frac{27}{34}$ cm
- $\frac{35}{81}$ cm
Show Solution
The Correct Option is B
Solution and Explanation
Was this answer helpful?
0
Top Questions on Newtons law of gravitation
- What is the gravitational force between two 5 kg masses placed 2 meters apart? (Take \( G = 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \))
- MHT CET - 2025
- Physics
- Newtons law of gravitation
- Two bodies of masses \( m_1 = 5 \, \text{kg} \) and \( m_2 = 10 \, \text{kg} \) are placed 2 meters apart. What is the gravitational force between them?
- MHT CET - 2025
- Physics
- Newtons law of gravitation
- A 90 kg body placed at \( 2R \) distance from the surface of the earth experiences gravitational pull of:
(\( R \) = Radius of Earth, \( g = 10 \, \text{ms}^{-2} \)).- JEE Main - 2024
- Physics
- Newtons law of gravitation
- The weight of an object measured on the surface of earth is 300 N. What will be the weight of the same object at depth R/4 inside the earth? (Given R = Radius of earth)
- Want to practice more? Try solving extra ecology questions todayView All Questions
